以下实例演示了使用多个 catch 来处理链试异常:
/* author by dba.cn Main.java */ public class Main{ public static void main (String args[])throws Exception { int n=20,result=0; try{ result=n/0; System.out.println("结果为"+result); } catch(ArithmeticException ex){ System.out.println("发算术异常: "+ex); try { throw new NumberFormatException(); } catch(NumberFormatException ex1) { System.out.println("手动抛出链试异常 : "+ex1); } } } }
以上代码运行输出结果为:
发算术异常: java.lang.ArithmeticException: / by zero 手动抛出链试异常 : java.lang.NumberFormatException